Buck Boost Regulator Peak to Peak Ripple Current of Inductor Expression Derivation

In this topic, you study How to derive an expression for Peak to Peak ripple current for Buck-Boost Regulator.


The buck-boost regulator can produce an average output voltage less than or greater than the dc source input voltage. Let us assume large filter capacitance C connected across the load so that output voltage remains almost constant. The Resistive load is considered.

Circuit diagram

The working of a buck-boost regulator is explained using the circuit diagram as shown in Figure 1. The switch ${S_1}$ shown in the circuit diagram can be a conventional thyristor i.e., SCR, a GTO thyristor, a power transistor, or a MOSFET.

Circuit diagram of buck boost Regulator

Waveforms

The typical waveforms in the converter are shown in Figure 2.

Waveform for buck boost Regulator

Mode of Operation Interval 1: –

The time interval is 0  ≤  t  ≤  ${T_{ON}}$. The switch ${S_1}$ is turned on. The circuit diagram for Mode of Operation Interval 1 is shown in Figure 3 and the corresponding waveforms are shown in Figure 2.

Circuit diagram of buck boost Regulator when switch S1 ON

From the waveform of voltage across the inductor, as shown in Figure 2, the equation for the inductor voltage write as

\[{v_L} = {V_S} \hspace{1cm}….(1)\]

The general equation relates voltage across the inductor and current passes through it as

\[{v_L} = L\frac{{d{i_L}}}{{dt}} \hspace{1cm}….(2)\]

Put Equation 2 in Equation 1 gives

\[L\frac{{d{i_L}}}{{dt}} = {V_S}…(3)\]

The waveform for current passes through inductor L as shown in Figure 2, Integrate Equation 3 using the maximum and minimum value of inductor current gives

\[\int\limits_{{I_{\min }}}^{{I_{\max }}} d {i_L} = \frac{{{V_s}}}{L}\int\limits_0^{{T_{ON}}} d t\]

or

\[{I_{\max }} – {I_{\min }}\hspace{0.1cm} =\hspace{0.1cm} \frac{{{V_S}}}{L}.{T_{ON}} \hspace{1cm}….(4)\]

Here $\Delta {I_L} = {\text{ }}{I_{\max }}\hspace{0.1cm} – {I_{\min }}$ is the peak to peak ripple current of inductor L and hence Equation 4 can be write as

\[\Delta {I_L} = \frac{{{V_S}}}{L}.{T_{ON}} \hspace{1cm}….(5)\]

Also

\[{T_{ON}} = \alpha T = \frac{\alpha }{f} \hspace{1cm}….(6)\]

Using Equation 5 and Equation 6 gives

\[\Delta {I_L} = \frac{{{V_S}}}{L}.\frac{\alpha }{f} \hspace{1cm}….(7)\]

Equation 7 describes the peak to peak ripple current of inductor L in buck-boost converter.

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